Min Max finder in an array of numbers

Instructions:

Create a function called minMax() that takes in an array of numbers and returns an object with the minimum and maximum numbers in the array.

Expected result:

minMax([2, 9, 5, 3, 8, 0]);
// Min: 0 and Max: 9

Solution:

function minMax(numbers) {
  if (Array.isArray(numbers)) {
    const min = Math.min(...numbers);
    const max = Math.max(...numbers);

    return { min, max };
  }
  return 'Not a valid array';
}

const {min, max} = minMax([2, 9, 5, 3, 8, 0]);

console.log(`Min: ${min} and Max: ${max}`);

Same solution using arrow function:

const minMax = (numbers) =>
  Array.isArray(numbers)
    ? { min: Math.min(...numbers), max: Math.max(...numbers) }
    : "Not a valid array";

const { min, max } = minMax([2, 9, 5, 3, 8, 0]);

console.log(`Min: ${min} and Max: ${max}`);

Test Values:

const { min, max } = minMax([2, 9, 5, 3, 8, 0]);
console.log(`Min: ${min} and Max: ${max}`);

Output:
Min: 0 and Max: 9

const { min, max } = minMax([21, 19, 50, -3, -8, 0]);
console.log(`Min: ${min} and Max: ${max}`);

Output:
Min: -8 and Max: 50